f(x) = 2x-1; g(x) = x^2 - 4

a) Graph f and g on the same Cartesian plane
b) Solve f(x) = g(x)
c) Use the result of part (b) to label the points of the intersection of the graphs of f and g
d) Shade the region for which f(x) g(x), that is, the region below f and above g

Question

f(x) = 2x-1; g(x) = x^2 - 4

a)	Graph f and g on the same Cartesian plane
b)	Solve f(x) = g(x)
c)	Use the result of part (b) to label the points of the intersection of the graphs of f and g
d)	Shade the region for which f(x) > g(x), that is, the region below f and above g

anonymous · Answer

2x-1 is a straight line, x^2 - 4 is a parabola

anonymous · Answer

$$2x-1 = x^2 - 4$$

anonymous · Answer

i got x = (-1,0) and x= (3,0)...is that right?

anonymous · Answer

yes

anonymous · Answer

so those are the x-int of the parabola?

anonymous · Answer

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