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sqrt27x^4y^6
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since 27 is not a perfect square we leave it alone, divide the exponents of the variables by two , since sqrt means raised to 1/2. and then put out the varables with the exponents outside the radical :)
hi, do ya want to simplify this ? \[\sqrt{27 \ \times \ x ^{4} y ^{6}}\] then.. \[(27x ^{4}y ^{6})^{1/2}\] \[3^{3 \times \frac{ 1 }{ 2 }} x ^{4\times \frac{ 1 }{ 2 }}y ^{6\times \frac{ 1 }{2 }}\] \[3^{\frac{ 3 }{ 2 }}x ^{2}y ^{3}\] Hope this will help ya out!!!!
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