Question

what is the solution set to the inequality 2x^2+5x less than 12

Answer 1

start with
\[2x^2+5x-12<0\] then see if you can factor it

Answer 2

no its wrong sorry

Answer 3

ans = -4<x<3/2

Answer 4

it would help maybe to actually solve it rather than write down an answer

Answer 5

can you explain it to me then

Answer 6

factor first
you get
\[(2x-3)(x+4)<0\]

Answer 7

factoring i cannot explain, you just have to grind it til you find it
once it is factored, you know the zeros are \(-4\) and \(\frac{3}{2}\)

Answer 8

since this parabola opens up, it is negative between the zeros and positive outside them
i.e. it is negative on \((-4,\frac{3}{2})\) and positive on \((-\infty, -4)\cup (\frac{3}{2},\infty)\)

Answer 9

i understand the factoring

Answer 10

you are asked for where it is negative
so your answer is \(-4<x<\frac{3}{2}\)

Answer 11

of course if you know where it is negative, you also know where it is positive as those are your only choices, unless of course it is zero

Answer 12

2x^2+5x-12<0
2x^2+8x-3x-12<0
2x(x+4)-3(x+4)<0
(2x-3)(X+4)<0
-4<x<3/2
x element of (-4,3/2)

Answer 13

yes if it would have asked for positive then ans would have been (−∞,−4)∪(32,∞)

Answer 14

but its clearly given function <0