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Sin(1/2 cos^-1 3/5)
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\[sin\left(\frac{cos^{-1}\left(\frac{3}{5}\right)}{2}\right)\] Alright...so in degrees or radians
\(\cos(2x) = 1 - 2\sin^{2}(x) \implies \sin(x) = \pm\sqrt{\dfrac{1 - cos(2x)}{2}}\implies\sin(x/2) = \pm\sqrt{\dfrac{1 - cos(x)}{2}}\)
I wondered if that would fit. \(\sin(x/2) = \pm\sqrt{\dfrac{1 - cos(x)}{2}}\)
That is a beautiful simplification @tkhunny! Neat too because we could use the property: \[cos[cos^{-1}(x)]=x\]
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