Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

(5a-3)(2a+4)

OpenStudy (anonymous):

What are you trying to do with this?

OpenStudy (anonymous):

Multiply

OpenStudy (anonymous):

I foiil?

OpenStudy (anonymous):

Yes:)

OpenStudy (anonymous):

and what do you get?

OpenStudy (anonymous):

1080?

OpenStudy (anonymous):

If you foil it then you would get \[10a ^{2}+14a-12\]

OpenStudy (anonymous):

Do you understand how I got that?

OpenStudy (anonymous):

No how'd you get that?

OpenStudy (anonymous):

Ok so the original problem is (5a-3)(2a+4). Foil stands for First, Outside, Inside, and Last. So, you would start by multiplying the first two terms.

OpenStudy (anonymous):

\[5a \times 2a\] 5 x 2 = 10 a x a = \[a ^{2}\]

OpenStudy (anonymous):

Outside: 5a x 4 = 20a Inside: -3 x 2a = -6a Last: -3 x 4 = 12

OpenStudy (anonymous):

put it together and you have \[10a ^{2}+20a-6a-12\]

OpenStudy (anonymous):

combine like terms 20a - 6a = 14a

OpenStudy (anonymous):

Yo wait I had that but instead I wrote 10a+20a+(-6a)+(-12) I think adding the positive sign messed me up

OpenStudy (anonymous):

ok then:) don't forget that it's \[10a ^{2}\] not 10a

OpenStudy (anonymous):

so thats 100 right?

OpenStudy (anonymous):

no the answer is 10a^2 +14a−12 unless you know what a is or what to replace it with you cannot get an answer without a variable.

OpenStudy (anonymous):

do you understand that?

OpenStudy (anonymous):

Yeah I get it now, Thank you

OpenStudy (anonymous):

You're welcome:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!