Question

Rationalize the denominator

Answer 1

You have:
\[\frac{\sqrt{-36}}{(2-3i)(3+2i)}=\frac{6i}{6+4i-9i-6i^2}=\frac{6i}{6+4i-6(-1)}=\frac{6i}{6+4i}\]

Answer 2

\[\frac{6i}{5-i}\times\frac{5+i}{5+i}=\frac{-6+30i}{26}=\frac{-3+15i}{13}\]

Answer 3

2-3i+3+2i=5-i

Answer 4

@Mertsj is that the final answer?

Answer 5

yes

Answer 6

I got something diferent

Answer 7

That's because you did not pay attention to the fact that the denominator said + and not x.
Also you did not rationalize the denominator.

Answer 8

OHHHH right sorry

Answer 9

Here are the options

Answer 10

Why did you post the list of answers?

Answer 11

because I was showing the options. I dont see urs

Answer 12

The very first thing I posted contains the answer. Did you even look at it?

Answer 13

yeaah. Hold on

Answer 14

ok sorry I wasnt looking correctly ! Thnks so much

Answer 15

yw

Answer 16

one more thing! When your doing descending order...do u do it from the numbers highest to low or exponents highest to low

Answer 17

@Mertsj

Answer 18

high to low descending means go down as in, "The debutante descended the spiral staircase."

Answer 19

Yeah so thats with numbers not exponent correct?

Answer 20

exponents.

Answer 21

Not coefficients

Answer 22

hm ok so lets say 14f^3 +^3f^2 -6f^8 (just made it up) U get -6f^8 +14f^3 +3f^2

Answer 23

If you want to put it in descending order that is what you get.

Answer 24

Ok cool thanks

Answer 25

yw