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If f(x) = −3 e^(x+3) + e^(1) then f′( 0 ) =
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f'(0) = -3e^3 = -60.25
@cheerosss
how did u solve it though
the derivative of -3e^(x+3) remains the same, but the derivative of e^1 is 0 (its a constant) so sub in zero and solve algebraically
@cheerosss
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o wow it was that easy thanks man i appreciate!!!
yeah... sure
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