Never solved this type of thing before, am I right?

Solve the following equation. If necessary, enter your answer as an expression involving natural logarithms or as a decimal approximation that is correct to at least four decimal places.
2^(2x+6)=3^(x-46)

x = 0.9086 (don't think I am).

Question

Never solved this type of thing before, am I right?

Solve the following equation. If necessary, enter your answer as an expression involving natural logarithms or as a decimal approximation that is correct to at least four decimal places.
                   2^(2x+6)=3^(x-46)

x = 0.9086 (don't think I am).

mathstudent55 · Answer

Take the log of both sides.

anonymous · Answer

$$ 2^{2x+6}=3^{x-46} $$
$$(2x+6)\ln(2)=(x+46)\ln(3)$$ and a raft of algebra to solve for $x$