Question

what is the x-intercept of the parabola. y=-3x^2+12x-9

Answer 1

is it (9,3)

Answer 2

put y=0 and solve for x

Answer 3

The x-intercepts are the points where the coordinate of the parabola equals 0, i.e. y = 0.

So, equating y to 0, we get:
\[-3x^2 + 12x - 9 = 0\]
\[-3x^2 +9x +3x - 9 = 0\]
\[(x-3)(3x-3)=0\]
\[x=3, x=1\]

Those are the x-intercepts.