Calculus II Inverse functions,

Can you please help me solve this exercise: http://screencast.com/t/HbZtHNM3pwN

Question

Calculus II Inverse functions,


Can you please help me solve this exercise: http://screencast.com/t/HbZtHNM3pwN

hartnn · Answer

did try u=tan x ? 
du =... ?

hartnn · Answer

and invese functions? O.o

christos · Answer

I tried tan but I got it wrong along the way , wait let me see again..

anonymous · Answer

he's right and after integration it will be sin^-1 u den substitute u=tanx

christos · Answer

du = 2tanx + sec^2x dx ?

hartnn · Answer

after the substitution, what did your integration turn into ?
in terms of u

hartnn · Answer

no, u= tan x
du = sec^2 x dx 
thats it!

christos · Answer

but its tan^2

hartnn · Answer

so, the denominator will be $\sqrt{1-u^2}$
whats the harm in it ?

christos · Answer

oook

christos · Answer

sin^-1(tanx) + C ? thats it 
?

hartnn · Answer

yes, thats acceptable, but you can express that algebraically also...if u need to.

christos · Answer

naaah its ok ! that will do , ty

hartnn · Answer

welcome ^_^

christos · Answer

= )