Question

Calculus II Inverse functions,


Can you please help me solve this exercise: http://screencast.com/t/HbZtHNM3pwN

Answer 1

did try u=tan x ?
du =... ?

Answer 2

and invese functions? O.o

Answer 3

I tried tan but I got it wrong along the way , wait let me see again..

Answer 4

he's right and after integration it will be sin^-1 u den substitute u=tanx

Answer 5

du = 2tanx + sec^2x dx ?

Answer 6

after the substitution, what did your integration turn into ?
in terms of u

Answer 7

no, u= tan x
du = sec^2 x dx
thats it!

Answer 8

but its tan^2

Answer 9

so, the denominator will be \(\sqrt{1-u^2}\)
whats the harm in it ?

Answer 10

oook

Answer 11

sin^-1(tanx) + C ? thats it
?

Answer 12

yes, thats acceptable, but you can express that algebraically also...if u need to.

Answer 13

naaah its ok ! that will do , ty

Answer 14

welcome ^_^

Answer 15

= )