Question

Inverse functions,

Is this correct or no?

Answer 1

u= e^-x
right ?
so, du = -e^-x
where did negative sign go ?

Answer 2

hm

Answer 3

so its the same thing but with swapped signs at the final answer ?

Answer 4

e^ln x = x

Answer 5

How do I use that ? :/

Answer 6

For Example: - there is two mirror when you stand on the first mirror than your whole body is coming in that mirror but in second mirror that the whloe first mirror and your image is also seen in that mirror this the inverse function

Answer 7

wow, never thought i that way....but we r not talking about inverse fn, even though the Q says so...christos has an habit of writing inverse function everywhere :P

Answer 8

:D

Answer 9

e^{ln (2/sqrt 3)} = 2/sqrt 3
so whats sin inverse of (sqrt 3/2) ??

Answer 10

pi/3 !

Answer 11

but .... why this time we placed the limits AFTER replacing u ? I thought it was Before replacing u ?

Answer 12

also its e^(-x) not e^x

Answer 13

we can do it either way...if you already changed the limits, then forget you do not use earlier limits, and if you have not changed the limits, do a re substitution and use earlier limits

e^-x = 1/e^x

Answer 14

Why did you swap these http://screencast.com/t/HJvlnm1MOwVm ?

Answer 15

nvm I got it -_-

Answer 16

yeah, e^-x was there, so 1/e^x
so num and denom swapped

Answer 17

so whats sin invers of 1/2 ?

Answer 18

im sorry but idk :(

Answer 19

that's my table http://screencast.com/t/nCrWNwkY

Answer 20

i can see a 1/2 there in sin theta row

Answer 21

how silly of me -_- it's pi/6

Answer 22

lastly, pi/3-pi/6 = ...
is your final answer :)

Answer 23

Pheu thankss

Answer 24

welcome ^_^