Treatment of 2-bromo-2-methylbutane with KOH in ethanol yields a mixture of two alkene products. What are their likely structures?
After attempting the problem I got one of them being 2-methylbut-1-ene and I was even more unsure of the other. I'm assuming it could possibly be 2-methylbut-2-ene. Also, I'm thinking there would also be KBr and water in the solution as well, but that isn't really what the problem was asking for. Could anyone let me know if this is correct? If not, could anyone explain the error that was made?
Thanks.

Question

Treatment of 2-bromo-2-methylbutane with KOH in ethanol yields a mixture of two alkene products. What are their likely structures?
After attempting the problem I got one of them being 2-methylbut-1-ene and I was even more unsure of the other. I'm assuming it could possibly be 2-methylbut-2-ene. Also, I'm thinking there would also be KBr and water in the solution as well,  but that isn't really what the problem was asking for. Could anyone let me know if this is correct? If not, could anyone explain the error that was made?
Thanks.

abb0t · Answer

This is an E$_1$ reaction. Does that help?

abb0t · Answer

I believe that the product forms: product + enantiomer.