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Mathematics 18 Online
OpenStudy (anonymous):

**GIVING MEDAL + FAN** Determine whether y varies directly with x. If so, find the constant of variation k and write the equation.

OpenStudy (anonymous):

OpenStudy (anonymous):

@pitamar @lizzylou169 Please help ;-;

OpenStudy (anonymous):

so, you got this one? i see it's closed

OpenStudy (anonymous):

No I didn't get it :/ I just ran out of time, but I can still answer it! :D

OpenStudy (anonymous):

Please help. Lol

OpenStudy (anonymous):

Ok, you see on the left a list of x values, what's the differences between them?

OpenStudy (anonymous):

what are* =|

OpenStudy (anonymous):

When, they all increase by one? (7, 8, 9, 10)

OpenStudy (anonymous):

I feel like that wasn't the answer to your question however.

OpenStudy (anonymous):

yes, and the y values increase by how much?

OpenStudy (anonymous):

By 2.

OpenStudy (anonymous):

ok how would you write a simple function that makes y grow by 2 for every increase of 1 in the x?

OpenStudy (anonymous):

It wouldn't be this one, but it's a start =]

OpenStudy (anonymous):

uuuhmm.... y+2 > 1x I don't know, I'm really bad at these :/

OpenStudy (anonymous):

\[ y = 2x \] since every x you add, adds 2 to the y

OpenStudy (anonymous):

therefore if x = 1... 2*1 = 2. if x = 2... 2 * 2 = 4... so on. right?

OpenStudy (anonymous):

Oh, I see! yes.

OpenStudy (anonymous):

ok, this isn't exacly the function to those values though. let's see why. calculate f(7)

OpenStudy (anonymous):

What's f...? multiply 7 by what?

OpenStudy (anonymous):

\[ f(x) = 2x \] wrote it as \[y = 2x \] before.. hehe

OpenStudy (anonymous):

so 2x(7) then? o.o

OpenStudy (anonymous):

f(7) means x = 7. and by \[ f(x) = 2x \] that means...

OpenStudy (anonymous):

OH!

OpenStudy (anonymous):

yes. so f(7) is what?

OpenStudy (anonymous):

14x?

OpenStudy (anonymous):

God, I know I'm wrong.

OpenStudy (anonymous):

just 14 hehe it's like saying \[ y = 2x \\ x = 7 \\ y = 2 \cdot 7 = 14 \]

OpenStudy (anonymous):

Oh, So I was sort-of getting it :D

OpenStudy (anonymous):

ye but 14x and 14 are different things, and it could get you in alot of troubles. so make sure to understand it all.

OpenStudy (anonymous):

what is f(9) for example?

OpenStudy (anonymous):

f(9) = 18? Just 18. No x :D

OpenStudy (anonymous):

ye, ok

OpenStudy (anonymous):

ok, so now we know how to make a function that increases by 2 for each increase of 1 on the x. but they tell you that their function, let's call it g(x) for now has the following value \[ g(7) = 11 \\ g(8) = 13 \\ g(9) = 15 \]

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

yes, right.

OpenStudy (anonymous):

calculate your f(7), f(8), f(9), and compare. what's the difference in all cases from the matching g(x)?

OpenStudy (anonymous):

f(7) = 14 f(8) = 16 f(9) = 18 Sorry, but what do you mean by matching g(x)? Because if it's how much (basically) "14 *f(7)* is away from 11*g(7)*." then it would be 3.

OpenStudy (anonymous):

ye basically. it seems by all those values that \[ f(x) - g(x) = 3 \\ f(7) - g(7) = 14 - 11 = 3 \\ f(8) - g(8) = 16 - 13 = 3 \] ...

OpenStudy (anonymous):

so that means we have to subtract 3 from every value on our f(x) to get g(x).. right?

OpenStudy (anonymous):

right!

OpenStudy (anonymous):

so let's make a new function... which would be f(x) - 3. let's call it h(x). remember, what f(x) really is? now try and write it

OpenStudy (anonymous):

you know what let's keep it simple.. \[ f(x) - g(x) = 3 \\ f(x) - 3 = g(x) \]

OpenStudy (anonymous):

so would it be h(-3)?

OpenStudy (anonymous):

since you know what f(x) ןד, what is g(x) in here?

OpenStudy (anonymous):

or h(7, 8, 9)

OpenStudy (anonymous):

forget about h(x). i was over complicating it. \[ f(x) - g(x) = 3 \\ f(x) - 3 = g(x) \] you know what f(x) really is. so find g(x) =] just simple replacing

OpenStudy (anonymous):

to remind you \[ f(x) = 2x \]

OpenStudy (anonymous):

(Sorry, Im juggling 2 question at one time. no prob) so would g(x) = 3x?

OpenStudy (anonymous):

or -3x?

OpenStudy (anonymous):

once again. \[ f(x) - g(x) = 3 \\ f(x) - 3 = g(x) \] you know the definition of f(x). use it and get g(x)

OpenStudy (anonymous):

Well, all I can think of is f(3) x 2x = 6...so g(6).

OpenStudy (anonymous):

you're too confused. forget everything in your mind and follow me =]

OpenStudy (anonymous):

Alright :D

OpenStudy (anonymous):

we know that in order to make the value increase by 2 for each 1 x we define the following \[ y = 2x \\ f(x) = 2x \] both are pretty much the same... just second one is a function that could get a value and be in thie case \[ f(value) = 2 \cdot value \] that's the point of 'x' in there. now. we know that \[ f(7) - g(7) = 3 \\ f(8) - g(8) = 3\\ f(x) - g(x) = 3 \\ f(x) - 3 = g(x) \] since f(x) = 2x.. \[ g(x) = f(x) - 3 = 2x - 3 \\ g(x) = 2x - 3 \]

OpenStudy (anonymous):

g(x)=2x−3 subtracting? It wouldn't be g(-1), would it?

OpenStudy (anonymous):

nonono.... it's not 2 - 3... it's 2x - 3.. and you leave it that way, because you have no idea what 'x' is.. that's the point. if it's g(5) then \[ g(5) = 2 \cdot 5 - 3 = 10 - 3 = 7 \\ g(8) = 2 \cdot 8 - 3 = 16 - 3 = 13 \\ g(x) = 2 \cdot x - 3 \]

OpenStudy (anonymous):

Oh I see! it was a formula! psh, i knew that ;D So then for 15 (the next one) it would be g(9) = 2 x 9 - 3 = 15? :D

OpenStudy (anonymous):

ye. =]

OpenStudy (anonymous):

well, I guess that's it hehe, good luck with next one i guess

OpenStudy (anonymous):

Thank you so much! I really needed help with that one. *whew*

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