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A baseball player hits a ball toward the outfield. The height h of the ball in feet is modeled by h(t) = -16t^2 + 22t + 3, where t is the time in seconds. In addition, the function d(t) = 85t models the horizontal distance d traveled by the ball. If no one catches the ball, how long will it stay in the air?
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its height is 0 when it hits the ground so -16t^2 + 22t + 3 = 0
Yes that's as far as I got. I'm not sure how to go from here to find the zeros since I don't see a way to factor.
right - so you can use the quadratic formula to get the zeros
= [-22 +/- (sqrt(22^2 - 4 * -16*3) ] / -32
Okay I'm not getting anywhere. Sorry!
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