Find the equation of the tangent line to the
graph of
3y^2 − xy − 8 = 0,
at the point P = (10, 4).
A. 7y + 2x = 8
B. 7y = 2x + 8
C. 13y = 4x + 12
D. 13y + 4x = 12
E. 5y = 2x

Question

Find the equation of the tangent line to the
graph of
3y^2 − xy − 8 = 0,
at the point P = (10, 4).
A. 7y + 2x = 8
B. 7y = 2x + 8
C. 13y = 4x + 12
D. 13y + 4x = 12
E. 5y = 2x

anonymous · Answer

It's B)

A Tangent line has to have the same gradient at that point so differentiate to get

$$\frac{ -y }{x - 6y }$$. Put in your (10,4) and you get a gradient of 2/7 at that point :)

anonymous · Answer

Thank you so much! @dmot7291

anonymous · Answer

No problem, glad I could help :)