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Mathematics 22 Online
OpenStudy (anonymous):

–3 ≤ n + 6 ≤ 7

OpenStudy (jdoe0001):

when you have a left-side and a right-side you'd add or multiply to both sides to solve for whatever variable in this case you have, a left-side a middle-side and a right-side same thing, you'd just have to do it for all 3 sides –3 ≤ n + 6 ≤ 7 left middle right

OpenStudy (anonymous):

thank you jdoe:)

OpenStudy (anonymous):

but what would the answer be though?

OpenStudy (anonymous):

Well, unless my head is melting... which is quite possible Let's separate this: \[ -3 \le n+6 \quad\quad\text{ and } \quad\quad n+6 \le7 \\ -9 \le n \quad\quad\quad \text{ and } \quad\quad n \le 1 \\ -9 \le n \le 1 \]

OpenStudy (jdoe0001):

well... subtract 6 from all sides

OpenStudy (anonymous):

n ≤ 3 and n ≤ 7 n ≥ 9 and n ≤ 7 wold be one of those

OpenStudy (jdoe0001):

well... notice pitamar 's lines... same thing, it's just a way to do it piecewise, but the answer is correct

OpenStudy (anonymous):

Ironically I liked your way better...

OpenStudy (anonymous):

lol thank you both this helped

OpenStudy (anonymous):

I don't know which to give the best rsponce too.....

OpenStudy (anonymous):

him

OpenStudy (jdoe0001):

\(\bf -3 \le n+6 \le 7\\ \quad \\ \textit{let us subtract 6 from all 3 sides}\\ \quad \\ -3-6 \le n\cancel{+6-6} \le 7-6\implies -9 \le n \le 1\)

OpenStudy (anonymous):

ok thank you:) :*

OpenStudy (jdoe0001):

yw

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