Question

Find the equation of the line perpendicular to the graph of −4x−y=4 that contains the point (−2,−2).

Answer 1

y+2=-4(x+2)

Answer 2

Begin by rearranging your equation so that it is in the form

\[y=mx+b\]

From there, determine your slope, namely the value of m.

The slope of a perpendicular line is the negative reciprocal of the slope of the original line. Using that, and your point (-2,-2), use the point slope formula

\[y-y_{1}=m(x-x _{1})\]

Where m is your slope of the perpendicular line and y1 and x1 are your x and y values given in your point on the graph. Solve the given expression for y.

Answer 3

-4x-4=y
slope of dis line is -4.which is m1.
for perpencilar lined condtion is, m1*m2=-1
-4*m2=-1
m2=1/4

Answer 4

dis is the slope of required equation bcoz the lines are perpendicular.if they were parallel,slopes would have benn same.now eqn will be,
(y-y1)=m(x-x1) where m is the slope which we found out

Answer 5

(y-(-2))=1/4(x-(-2))
y+2=1/4(x+2)
4(y+2)=x+2
4y+8=x+2
4y-x=2-8
4y-x=-6

Answer 6

thanks