Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

What are the x-intercepts for the graph of http://i.imgur.com/gj1ahe1.png (2,0) and (-6,0) (-2,0) and (6,0) (0,-1) and (0,6) (0,1) and (0,-6)

Directrix (directrix):

x-intercepts are where the graph crosses the x-axis. The y-coordinate of an x-intercept is always zero because to get on the x-axis, the y-value has to be zero. Knowing that, then what value of x makes (x - 2) = 0 AND what value of x makes (x + 6) = 0 ? @mikeshaw

Directrix (directrix):

Hint: These two options are out because they have y-coordinates that are not zero. So, these points cannot lie on the x-axis and cannot be x-intercepts because of that. (0,-1) and (0,6) (0,1) and (0,-6)

Directrix (directrix):

@mikeshaw

OpenStudy (anonymous):

it would be (0,-1) (0,6) the y coordinates cannot be negative right?

Directrix (directrix):

No. The y-coordinates of the x-intercepts will always be ZERO. That knocks out options C and D from being the correct answer. Try again. @mikeshaw

OpenStudy (anonymous):

Y cannot be negative right?

OpenStudy (anonymous):

i'm confused on this problem. I think it would be NB then

Directrix (directrix):

Y HAS to be ZERO.

Directrix (directrix):

The answer is one of these two: (2,0) and (-6,0) (-2,0) and (6,0)

Directrix (directrix):

To choose, do this: Knowing that, then what value of x makes (x - 2) = 0 AND what value of x makes (x + 6) = 0 ? @mikeshaw

Directrix (directrix):

If x - 2 - 0, then x = ? Also, if x + 6 = 0, then x = ?

OpenStudy (anonymous):

x=6 then

Directrix (directrix):

No. x + 6 = 0 -6 - 6 ------------ x = -6 That goes with (-6,0)

OpenStudy (anonymous):

sorry i meant to type -6

Directrix (directrix):

(x - 2) = 0 +2 +2 ----------- x = 2 That goes with (2,0)

Directrix (directrix):

(-6,0) and (2,0) are the x-intercepts.

OpenStudy (anonymous):

thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!