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the dy/dx of x^2 + y^2 - 6x + 4y = 0.
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\[2x+2yy'-6+4y'=0\] solve for \(y'\)
-2x+6/ 2y+4
@satellite73
It's right :)
oh sorry i didn't do it yes, it is right, but you might want to cancel the 2
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so its.. -x+6/ y+4
@satellite73
-x+3/y+2
@silverxx yes you are right
(-x+3)/(y+2) IS THE FINAL ANSWER @silverxx .
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@CGGURUMANJUNATH yes you are right i forgot to take 2 as common factor!!
NO PROBLEM IT SOMETIMES HAPPENS LIKE THAT WE TEND TO MAKE MISTAKES @prince90p .LOL.
yeah that's right ^_^
:)
thank you guys :)
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you are most welcome.!
wc.
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