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Geometry 10 Online
OpenStudy (anonymous):

What is the area of the shaded segment shown at the right? Round your answer to the nearest tenth.

OpenStudy (anonymous):

|dw:1381239699308:dw|

OpenStudy (jack1):

...which part is shaded... the triangle or the segmant?

OpenStudy (jack1):

@wolfgirl ...?

OpenStudy (jack1):

|dw:1381239980234:dw|

OpenStudy (jack1):

|dw:1381240029352:dw|

OpenStudy (anonymous):

Oh, sorry... The segment is shaded.

OpenStudy (jack1):

ah, cool so an easy way to do this is just geometry: realise that right angle = 90 degrees = 1 quarter of area of circle so Area of quarter = area of circle / 4 = area of triangle + area of segment... this making sense so no special formulas needed yet

OpenStudy (jack1):

Area of quarter = area of circle / 4 = pi r^2 / 4 = (pi x 4^2 )/4 = 4pi 4pi = area of triangle + area of segment 4pi = 1/2 x base x ht + area of segment 4pi = 1/2 x 4 x 4 + area of segment 4pi = 1/2 x 16 + area of segment 4pi = 8 + area of segment so area of segment = (4pi - 8) m^2 im sure you can skip most of the lines above in your workings, i just wanted everything to be clear does that all make sense tho @wolfgirl ?

OpenStudy (anonymous):

Yes, I'm gonna try that for myself and see if it works :) I'll let you know if I need anymore help. Thanks!

OpenStudy (jack1):

|dw:1381240756157:dw|

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