Question

maximum height

Answer 1

keep getting the wrong answer.

Answer 2

@goformit100

Answer 3

@UnkleRhaukus

Answer 4

@UnkleRhaukus i keep getting 3363.8 m

Answer 5

but it is wrong

Answer 6

i can't see your working

Answer 7

okay i did max height = t*236(24.08) - 4(24.08)^2

Answer 8

i mean 4.9 for 4

Answer 9

nevermind i see the problem

Answer 10

thanks for looking any way @Loser66 and @UnkleRhaukus

Answer 11

@UnkleRhaukus what do you get? I get the max height is 2841.63 m

Answer 12

\[y(t)=y_0+v_0t+\tfrac12at^2\longrightarrow v_0t-\tfrac12gt^2\\
v(t)=v_0+at\qquad\qquad\longrightarrow v_0-gt\\v(t)=v_0-\tfrac12gt_\text{max}\]
\[v(t_\text{max})=v_o-gt_\text{max}=0\qquad t_\text{max}=\frac{v_0}{g}\]

Answer 13

\[y(t_\text{max})=v_0t_\text{max}-\tfrac12gt_\text{max}^2\]

Answer 14

to me, at the highest position, V =0, and \(V^2 = V_0^2 +2aS\) where a = -9.8, so,
S = \(\dfrac{V_0^2}{2*9.8}= 2841.63\)

Answer 15

\[y(t_\text{max})=v_0(\frac{v_0}g)-\tfrac12g\big(\frac{v_0}g\big)^2=\frac{v_0^2}{2g}\]

Answer 16

yup thats what i got...thank you all

Answer 17

2.8e3