If the terminal side of the angle θ is on the line y=- 1/4x and is in quadrant II find the sinθ and cotθ. #HELPPP :/
Did you start with a sketch?
no.
It can help you find the reference angle you need by making a right triangle.
thanks.
if y =(-1/4)x then tanθ=-1/4 , So the angle would be tan^-1(-1/4)=14, since its in quadrant II sinθ is positive =0.24 and cosθ is negative = -0.97
https://www.desmos.com/calculator/f4ii9pdkrh With that triangle, or another on the same line, I can find the trig ratios for the angles. Then 180- the angle from the origin down to the x axis is the measure of the one you want.
Oops ...down from the line that goes through the origin....
Which is basically the same thing ikram002p said. He is just using the slope alone, which is what gives me the ratio of the sides as well.
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