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Mathematics 18 Online
OpenStudy (anonymous):

4. Simplify (5x 2 + 3x2) + (4x + 3) Is it 3x2 + 9x + 1 or 3x2 + 9x - 1 ???

OpenStudy (anonymous):

*The 3x2s should be 3x^2s Sorry!

OpenStudy (anonymous):

I'm not sure I'm getting it.. \[ (5x^2 + 3x^2) + (4x + 3) = 8x^2 + 4x + 3 \] But I don't see any use for the ()s in here... What am I missing?

OpenStudy (jdoe0001):

the () are there just to emphasize grouping

OpenStudy (anonymous):

still.... I don't see any reason to group anything.. especially the second part.

OpenStudy (jdoe0001):

well... lemme put it this way.. if you take a driving test, they put some orange cones about the road you could say... what's up with those orange cones in the road, why can't I just drive about the street? well the idea is that, the cones are there just to represent such so, it's just a red herring

OpenStudy (anonymous):

Right, so is is 3x^2 + 9x + 1 or 3x^2 + 9x - 1 ?

OpenStudy (anonymous):

I can't tell if it's addition or subtraction

OpenStudy (anonymous):

Eh idk... There are many cases that I would see why grouping is good, not this time.. again, especially the second part. btw, do you see a way to simplify this any further? I can't.. I could say that 3 and 1 are the components of 3.. and just in case 3 + 1 = 4.. but I can't find anyway to get the coeffecient of x^2 to be 8 with (ax+c)(bx+d)

OpenStudy (jdoe0001):

hmmm you can factor it, but I don't think it's required

OpenStudy (jdoe0001):

the grouping in this case, I assume it's because is algebra 1 or so, thus is reasonable

OpenStudy (anonymous):

Well, meg.. I don't get any of those results as I said. Am I solving the right expression?

OpenStudy (jdoe0001):

\(\bf (5x^2 + 3x^2) + (4x + 3)\implies \color{blue}{5x^2 + 3x^2}+4x + 3\\ \quad \\ \color{blue}{8x^2}+4x + 3\)

OpenStudy (anonymous):

what, colors?! damn I should learn latex better...

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