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differentiate and simplify: y=(3x)/(x^2 + 1)
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\[\Large y=\frac{3x}{x^2+1}\]Quotient Rule!\[\Large y'=\frac{\color{royalblue}{(3x)'}(x^2+1)-(3x)\color{royalblue}{(x^2+1)'}}{(x^2+1)^2}\]
So there is our quotient rule setup. We'll need to take the derivative of the blue parts. Any confusion? :o
not yet
y'= (3) * (x^2+1) - 2x * 3x / (x^2 +1)^2
mmmmm looks good.
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