for y=2/3x-2 where the slope is 2/3 and the y- intercept is -2 can someone help me Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences. ?

Question

anonymous · Answer

They already give you the line in slope-intercept method.
For graphing it you know the y intercept is -2 so put y=-2  on x=0 and just use some other coordinate

anonymous · Answer

wouldnt we use rise over run and like put a point on 2 and go to the right 3 ?

anonymous · Answer

well
$$
y = \frac{3}{2}x - 2
$$
Since this is a linear function, the graph that comes out is a straight line. And all we need to draw this line are 2 points.
You could take any 2 points you wish. let's say x=0 and x=1
$$
f(0) = \frac{3}{2} \cdot 0 -2 = -2 \
f(1) = \frac{3}{2} \cdot 1 -2 = \frac{3}{2} - \frac{4}{2}  = -\frac{1}{2}\
$$
And now just a ruler and to draw a line across them both..
In case you wanna find where it intersects with the X axis
$$
y = 0 \
\frac{3}{2}x - 2 = 0 \
\frac{3}{2}x  = 2 \
3x  = 4 \
x = \frac{4}{2}
$$
And for the intersection with Y axis.. we already have the result for x=0.

anonymous · Answer

is that correct ?

anonymous · Answer

Yes I would recommend this way:
Since you know the y intercept plot that.
Now make y = 0 to find the x intercept
2/3x-2=0
x=3
Plot (3,0): Now join the dots and you have your line

anonymous · Answer

thank you everyone