Question

how do I solve the following system of equations?
x=15+6y
9x+3y=21

Answer 1

plug the first equation into the second one's x

Answer 2

Ive gotten this far
9x+3y=21
9(15+6y)+3y=21

Answer 3

9(15+6y) +3y=21 and solve

Answer 4

okay, now distribute

Answer 5

Ik you distribute the 9 which would be 135+57y=21

Answer 6

good then subtract 135 from 21

Answer 7

so you get 57y= -114. divide the -114 by 57 and voila! you get your answer

Answer 8

k I did it right then

Answer 9

hope that helped

Answer 10

but what will I put in for x when I check my answer

Answer 11

so y=-2 right? take the -2 and plug it into y in either equation to get x

Answer 12

with it being 9x+3y=21

Answer 13

in both equations, x=3

Answer 14

how did you get that ?

Answer 15

sorry slowly getting the hang of this

Answer 16

its ok:)

Answer 17

because u used bothe equations to find y, they will also share the same x. so when y is plugged into one equation, x will equal 3. double check with the other equation and we also get 3 for x

Answer 18

is it clear now? or do you have more questions?

Answer 19

still trying to figure out how you get 3?

Answer 20

ok, we take the -2 that is y. you pick either equation, it does not matter. x=15+6(-2). x=15+(-12). x=3

Answer 21

oh ok I get it I am very sorry

Answer 22

it ok, happy to help :)

Answer 23

thank you for be patient with me

Answer 24

no prob.