QUADRATIC FUNCTIONS..
Write a quadratic function that represents a parabola that opens downward and has x-intercepts (2,0) and (14, 0).

Question

QUADRATIC FUNCTIONS..
Write a quadratic function that represents a parabola that opens downward and has x-intercepts (2,0) and (14, 0).

anonymous · Answer

so the factorization of the equation would be 
y=-(x-2)(x-14)             the negative is there so the parabola opens downwards
y=-(x^2-16x+28)        distributed the factors and now multiply by -1
y=-x^2+16x+28

the factors could have also been
y=(14-x)(2-x)  but i think it was easier to explain the other way

anonymous · Answer

hmmmmm.

anonymous · Answer

im having a hard time with these quadratics.

anonymous · Answer

do you need me to explain where i got the factors from or?

anonymous · Answer

yeah...I kinda got lost on the 16 and 28...

anonymous · Answer

so you know where it got the numbers from in the first step?
ok so for the second step it was distribution but i simplified it quick 
step by step it would be 
y=-((x^2-14x-2x+28) since|dw:1381289361895:dw|