Question

Simplify

Answer 1

\[\frac{ 4mn^2 }{ 2nm^4 }\]

Answer 2

\[2n/m^3\]

Answer 3

Divide the top and the bottom by \[2mn\] (the lowest powers you see of each prime number/variable: 2^1 and n^1 from the denominator and m^1 from the numerator)
to get:
\[\frac{2n}{m^3}\]

Answer 4

Okay thanks! That's the answer I got too.

Answer 5

\[\frac{ 4ba^4 }{ 4a^2b^3 } = \frac{ a^2 }{ b^2 }\]

Answer 6

is that right?

Answer 7

Yeah

Answer 8

Thank you!

Answer 9

:)