Question

find the derivative of y with respect to x, t, or theta; y=x^6lnx-1/3x^3

Answer 1

by putting " ln " for both sides we get

\[\ln y = \ln x ^{(6\ln x - 1)\div 3x ^{3}}\]

then we get this equation

\[\ln y = ( ( 6\ln x - 1) \div 3x ^{3} ) \times \ln x\]

this equation is long to derive but easier than its first form