Question

A valid password on a Web site contains 2 letters (A-Z, 26 total), followed by 4 digits (0-9). Letters and numbers can be repeated. The number of possible passwords equals @terenzreignz

Answer 1

Education first lol

Answer 2

There was no need for this... I'm pretty sure there is an "edit question" option ... not that I'd know :P

Answer 3

Ya know what... lol at least I took the choices out aha

Answer 4

Anyway, you know, this is almost the same as that computer thingy problem...
it's just that we renamed some stuff...

So, 6 character password, first two are letters...

For the first char, how many choices do you have?

Answer 5

6 ?

Answer 6

No... I mean, just the first character...which should be a letter, how many possibilities are there?

Answer 7

2

Answer 8

You're just not getting this are you?

First character is a letter... so it can be A right?

Answer 9

nahh TJ numbers and what not don't do me right lol but yeah it could be A - Z right?

Answer 10

Yes... so it could be A-Z... and those are how many? XD

Answer 11

26! >:D

Answer 12

Since we're dealing with these combinatorics, I will be rather sensitive to your use of the "!" symbol... you know it means factorial, strictly speaking XD

Answer 13

Ohhh yeah my bad. Here 26 *non-mathematical explanation point*

Answer 14

But yeah, twenty-six choices for the first char, and for each of these possibilities, how many choices for the second char (which should also be a letter) ?

Answer 15

If the second character is a letter as well wouldn't it be 26 choices also?

Answer 16

Yup...
So, 26 choices for the first char, and for each of these 26 choices, you get 26 choices for the second char.. that amounts to how many?

Answer 17

54

Answer 18

52**

Answer 19

Not even close :P

Answer 20

You don't add them together?

Answer 21

AA, AB, AC, AD ... AZ <---- these are already 26 possibilities for the first two chars...
BA, BB, BC, BD ... BZ <----- 26 more... that makes 52...

But what about
CA, CB, CC ... etc?


52? Not even close XD

Answer 22

That's a sh*t load of possibilities lol

Answer 23

Yes.. indeed... and I WILL emphasise that 52 is not even close...
Let me demonstrate it in a simpler fashion:

How many two digit numbers can you from with the digits 1,2, and 3?

Answer 24

*shrugs shoulders in hopeless confusion*

Answer 25

I gave you only three digits so that you can actually manually count them...
<baby talk voice>
Let's count them one-by-one!!!
11, 12, 13, 21, 22, 23, 31,32,33... that makes NINE!!!

Answer 26

Ohhhhh lol!!! Excuse my slow self PLEASE ughh

Answer 27

Okay, so, when you have 26 choices for the first letter and 26 more for the second letter, then the that means...?

Answer 28

Wait, so would it be 26 x 26? 0.o

Answer 29

I suspect a guess.

Answer 30

Is it?

Answer 31

It's a educated hypothesis :D

Answer 32

Yes

Answer 33

Well then, *justify* it.

Answer 34

Can you hold on I'll brb

Answer 35

Not for long... :D

Answer 36

Hey you there?

Answer 37

For the moment.

Answer 38

So... thought long and hard yet?

Answer 39

676 0.o

Answer 40

I know that, my question was WHY it's 26 x 26

Answer 41

After all, I need to be sure you weren't just guessing ;)

Answer 42

To be honest I was guessing lol but it's because there are 26 letters in the alphabet

Answer 43

This isn't healthy, you know... :/

Answer 44

For the first char, if you pick a specific letter, you can pick one of 26 letters to be the second char, right?

Answer 45

Lmfaooo I know why I just can't explain it! ergg

Answer 46

Right

Answer 47

Try.

Answer 48

Ok so like you said for every first char you have 26 options as well as 26 options for th second

Answer 49

So?
(Don't take my demand for an explanation the wrong way, I need you to actually understand how it works because, well, you guessed, and I should like to point out that your *first guess* was (sorry) not even close, and if you're going to be guessing, it's the first guess that determines whether you get it right or wrong....)

Answer 50

I understand where you're coming from

Answer 51

Honestly I know it it isn't a guess I just really can't explain it lol

Answer 52

I suggest you take a look at that computer question again...