Question

Someone helped earlier with setting these up. Can someone solve this for me please????
what is the binomial probability of the following:
P(X < 5)
P(X less than or equal to 10)
P(4 < X greater than or equal to 9)
n=12 p=.3 q=.7
Someone help me solve these please

Answer 1

what do you have to do calculations with? ti83 maybe?

Answer 2

excel would also be useful ....

Answer 3

P(0)+P(1)+P(2)+P(3)+P(4)

might be cumbersome by hand

Answer 4

sorry just got back I have both excel and ti

Answer 5

not sure how to use them though

Answer 6

ti is simply a function input ...

2nd, VARS, and pick the binomialcdf

Answer 7

input: n,p,x

Answer 8

in the case of x, you want to put in the biggest possible x;

in the case of X < 5, the biggest is x=4

in the case of X <= 10, the biggest is 10

Answer 9

ok what about the last example

Answer 10

the last part you have to pretty much do 3 terms:

Answer 11

P(4 < X greater than or equal to 9)

(1 2 3 4 5 6 7 8) 9 10 11 12

x = 12: subtract x = 8: add in x=3

Answer 12

in the first do I add all of them from 0 to four

Answer 13

i mighta read that wrong; can you rewrite it?

Answer 14

\[4\lt x\le9\] ???

Answer 15

rewrite what?

Answer 16

4 < X greater than or equal to 9

is rather hard to read thru

Answer 17

\[4 < X \le 9\]

Answer 18

ahh, then x = 9; and subtract off x=4

(0 1 2 3 4) 5 6 7 8 9

Answer 19

binormalcdf(n,p,9) - binormalcdf(n,p,4)

Answer 20

so:

binom(n,p,4)

binom(n,p,10)

binom(n,p,9) - binom(n,p,4)

Answer 21

that is for all 3?

Answer 22

i hope so ....

Answer 23

for the first one the calculator says .0013 and the answer in the book is 0.724?

Answer 24

cdf, not pdf

Answer 25

i get .732655... so you must have used the wrong function, or inputed a bad value

Answer 26

now it says -.9998

Answer 27

show me what your screen says

Answer 28

binomcdf(12,.3,4)

Answer 29

normalcdf(12, .3,4

Answer 30

i see i didnt scroll down enough

Answer 31

:)

Answer 32

now it says .723655

Answer 33

tada!!

Answer 34

you got .732655

Answer 35

yes, as i posted above

Answer 36

why is mine one under yours?

Answer 37

it says binomcdf ( 12, .3, 4) and the answer is .7236554696

Answer 38

if your talking about the order of the posts ... its most likely a browser issue.

i get .732655... so you must have used the wrong function, or inputed a bad value

Answer 39

now rnd to 3 decies

Answer 40

what do you get for the second

Answer 41

alot of 9s

Answer 42

mine too and it says the answer is .0002

Answer 43

do i subtract the .9999 from 1?

Answer 44

you can, but thats makes an odd reading of the x stuff to me

Answer 45

how would they get .0002

Answer 46

X less than or equal to 10

\[P(X\le 10)\]???

Answer 47

yes

Answer 48

P(0)+P(1)+P(2)+...+P(9)+P(10)

is binomcdf(12,.3,10)

Answer 49

which is about .9999

Answer 50

subtracting from 1 gives us NOT the probability ....

Answer 51

so make sure of the question

Answer 52

\[P(X \ge 10)\]

Answer 53

1 - binom(12,.3,9)

Answer 54

.00020637...

Answer 55

ok I see so when showing my work should I write out each equation?

Answer 56

it would be useful yes

Answer 57

so t

Answer 58

so the first would be 0-4 right? the second would be 0-9 and the third would be 5-9?

Answer 59

dont know sorry and thanks for all your help

Answer 60

0 to 4

1, minus (0 to 9)

(0 to 9), minus (0 to 4)

Answer 61

ok thank you i am going to post another in a moment that you might be able to help with. I just need help with the second part