M-M-MEDAL: Just want you to check some questions to see if I got it right and maybe answer some other questions.
Choose the slope-intercept equation of the line that passes through the point (6, 4) and is parallel to y = one thirdx - 3. y = 3x - 14 y = one thirdx + 2 y = -3x + 22 y = -one thirdx + 8
It MUST be B, right?
It is B
Thans, can you check another one for me, please? Thanks.
I'll try
Okay. Which of the following statements best describes the effect of replacing the graph of y = f(x) with the graph of y = f(x) + 20? The graph of y = f(x) will shift left 20 units. The graph of y = f(x) will shift down 20 units. The graph of y = f(x) will shift up 20 units. The graph of y = f(x) will shift right 20 units I chose C because I know that the y-intercept is the vertical part of the coordinate plane and positive is up.
I don't know how to do this one, sorry :[
It's okay. "-D
Anyone else?
@atlas @mathstudent55
since the line is parallel to y =(1/3)x -3 ; the slope of this line will remain the same you can write the new line as y = (1/3)x +c
You know at least one point that this line passes through So if you put the value of x and y from that point ->you can get c
Are we talking about C?
C. Pfft, sorry. I meant the second question.
b
no a
C is right in my opinion
Yeah, I think its C, too because it is the y-intercept...
You can do a simple test to find out..........let f(x) be a constant lets say 1 and see how y changes
Okay, I have this question that I have been looking at for too long: The following function defines a recursive sequence. f(0) = -4 f(1) = 12 f(n) = -3•f(n -1) - 2•f(n - 2); for n > 1 Which of the following sequences is defined by this recursive function? -4, 12, -28, 60, … -4, -12, -28, -60, … -4, 12, -18, 54, … -4, 12, -18, -54, …
Just keep on putting the value of n=1,2,3 and so on
in the function f(n)
Oh no, never mind. I think I know now...It is *-3, ight? Er, multiplying by -3. So 12 * -3 = -36...No, that is not the answer. GR.
you are leaving the 2nd term of f(n)
f(n) = -3•f(n -1) - 2•f(n - 2)
f(3) =-3*f(2)-2*f(1)
I think I simplified it to f(3) = -5 * f(2) * f(1)...
nope how can you do that??
Gr. -covers eyes- I did the like terms thingie. Sigh.
but there isn't any like term here..........
llllllllllllll. Then I dont now how to do this.
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