Question

y=IxI+4
vertex? axis of symmetry? slopes? which way it opens?? PLEASE HELP

Answer 1

Do you know how to sketch it? I think that's the easiest way to answer all that

Answer 2

barely? can u help?

Answer 3

Sure. You already have the equation in the form of y=mx+b where m is the slope and b is the gradient. So you have the slope and the gradient, can you sketch it now? Or, since it's a straight line, you can always take points x=any negative numbers, 0, and any positive numbers and plot it :)

Answer 4

ok now I know how to sketch it, PLEASE help with the answer portion part....????

Answer 5

starting with vertex

Answer 6

Alright so how does your graph look like?

Answer 7

1 line slants right crosses 1 on x-axis I think

Answer 8

the axis across

Answer 9

What about for when x is negative? Can you draw it here using the option below?

Answer 10

ok two lines, drawed

Answer 11

Can I see it? So I can check if you did it right and I can show you how to answer the rest?

Answer 12

I'm not sure if that's how it's supposed to be. Let's do it together. Let's use the range -8 to 8 with increments of 2 for x :) So we have Now can you sketch the graph?

Answer 13

yes

Answer 14

graphed it, still don't know vertex, axis of symmetry, slopes, and what way it opens though??

Answer 15

How does it look like? From the graph, vertex is the point where the graph is 'sharp', axis of symmetry is the line where the graph can be reflected symmetrically, and the what shape did you get? In what direction is it open or, forms a containment?

Answer 16

can I post a pic of my graph and u help me with the answer portion of question??

Answer 17

Yes. That's what I asked you to do :)

Answer 18

I'm sorry I'm trying to help 3 people at once.

Alright so at what point do you see the graph 'sharp' or forming a vertex?

Answer 19

0,4????

Answer 20

Not quite, look carefully. The point where the two seemingly separate lines meet. The V

Answer 21

1,2 ???

Answer 22

Yes :)

Now, if you draw a vertical line at going through that vertex, what do you see? Does the left side mirror the right side?

Answer 23

yes, but what points would I put for the axis of symmetry?

Answer 24

So an axis is a line. You can have point of symmetry(I think) but here you have a line. Since it is a vertical line, it contains all the y values for a specific x value, right? So you just put what the x value is there in the form x=a where a is the x value

Answer 25

doesn't make sense?? waz the axis of symmetry?? slopes???

Answer 26

Read what I said again. Axis of symmetry is a line, where it's left side mirrors the right side.

Answer 27

axis of symmetry is -2??

Answer 28

No. I told you the line goes through the vertex.

Answer 29

idk what it is then

Answer 30

cuz, I think she only wants one number??? idk ur confusing and still don't know answers )':

Answer 31

The line will have the same x value as the vertex. x=the x-value for your vertex

Answer 32

still don't ge it

Answer 33

is the axis o symmetry 1

Answer 34

Yes. x=1

Answer 35

yes!!! I got it right!!!! thanks.. what are the slopes?

Answer 36

????????

Answer 37

The slope can be found using the formula difference in y/difference in x

Answer 38

y2-y1 / x2-x1 ??????????

Answer 39

Yes. Now pick any 2 points along the same line and put the values into the formula.

Answer 40

thanks... help with 3 more??? they're easier...

Answer 41

I'm kind of tired...Maybe someone else can help you with those :) But you should be able to solve them with the same concept

Answer 42

pleaseeee???? it will only take a few minutes?? I partly understand them even please

Answer 43

Sure I'll try but I might not reply

Answer 44

W/out graphing identify -vertex, -axis of symmetry -slopes

Answer 45

8) y=2Ix+1I 9.) y=Ix-2I+3 10.) y=-1/2IxI-2

Answer 46

http://www.mathwebb.com/a2_notes_2-7.pdf Would this help?