Question

Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90. Find the numbers!!!

Answer 1

Try writing it the way we solved the last one.

Answer 2

ie follow the steps from last time.

Answer 3

I did, idk how to do it

Answer 4

Ley x = first number
Let y = second number

2(x + 3y) = 4
10y - 5x = 90

2x + 6y = 4
-5x + 10y = 90

10x + 30y = 20
-10x + 20y = 180

50y = 200
y = 4

If y = 4, then substitute y = 4 in the first equation,
2(x + 3y) = 4; 2(x + 12) = 4
So, x + 12 = 2, and x = -10

The first number is 10 and the second number is 4.

Answer 5

I messed up on the parenthesis, thanks:)