Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90. Find the numbers!!!

Question

agent0smith · Answer

Try writing it the way we solved the last one.

agent0smith · Answer

ie follow the steps from last time.

anonymous · Answer

I did, idk how to do it

anonymous · Answer

Ley x = first number
Let y = second number

2(x + 3y) = 4
10y - 5x = 90

2x + 6y =  4
-5x + 10y = 90

10x + 30y = 20
-10x + 20y = 180

50y = 200
y = 4

If y = 4, then substitute y = 4 in the first equation,
2(x + 3y) = 4; 2(x + 12) = 4
So,  x + 12 = 2, and x = -10

The first number is 10 and the second number is 4.

anonymous · Answer

I messed up on the parenthesis, thanks:)