Question

Can someone help me get this problem going?

Answer 1

So its kinda like this, first time is your independent variable, so

Answer 2

find the equation of the line through \((0,11)\) and \((3,33)\)

Answer 3

You would set up the left side of the equal sign as W(t),

Answer 4

with

\[\frac{ 33-11 }{ 3-0 }\]?

which is

\[\frac{ 22 }{ 3 }\]

Answer 5

what cronus said, but expressed properly:
w=22/3t

Answer 6

so for every t (year) there is a gain of 22/3 w (pounds)

Answer 7

Also the rate of change of weight, 22/3 would be added to 11 pounds, the baby's initial weight to get an equation of 22/3t+11.

Answer 8

I seem to get the wrong answer for that one when typed into the home works. It says in slope intercept form so am I missing the value of b?

\[w=\frac{ 22 }{ 3 }t+b\]

?

Answer 9

B would 11

Answer 10

*would be

Answer 11

22/3 is the slope (normally expressed as m) expressed as t here

Answer 12

The y intercept is when the independent variable is 0. Time is the independent variable, and when it equals 0,(the baby's birth) the weight is 11 pounds.

Answer 13

yes

Answer 14

ok so what am I still missing that gets the answer wrong still? I tried b as 11 in the formula and still wrong for the equation?

Answer 15

It would be w(t), I think

Answer 16

Not W

Answer 17

check your instructions for properly entering answers. You may have to use (22/3) parenthisis

Answer 18

No parenthisis are not needed any other slope forms I have had to include can just be wrote out like before

Answer 19

Wow dumb was a capital W....

Answer 20

Oh

Answer 21

That's a crappy program if you get an answer wrong for not using a capital :/

Answer 22

ok so if I where to continue the problem and it asked lets say how many pounds would she be at this age, i would put the year where T is and solve for W?

Answer 23

Yup!

Answer 24

Wow cool ok one more question for the problem, lets say I have points (3,-2) for a graph for the problem. How would you find the equation for that line. I am use to having the slope as well.

Answer 25

You would need an extra coordinate to find the slope, otherwise ts just any line that happens to have the point (3,-2) on its graph.

Answer 26

Well the graph look like this

p = 3, q = -2

Answer 27

Oh, you can also kinda see the y-intercept on the graph as (0,1) and another point, the x-intercept (1,0) on the graph

Answer 28

ok cause the line passes through the X and Y axis there correct, so how would you use this information to gain the line equation for that line?

Answer 29

So you would use the \[\frac{ y _{2} -y _{1}}{ x _{2}-x _{1}}\] formula

Answer 30

ok so I know the first set of points you use is the (3,-2)? or are we placing the x and y intrcepts into that equation?

Answer 31

To find slope, given the points (y1,x1) and (y2, x2) use the formula, and our y-intercept is right there on the graph, (0,1). Its your choice which two points to use.

Answer 32

so

\[\frac{ 0-1 }{ 1-0 }\]

Answer 33

slope is -1?

y=-1x? is the line equation

Answer 34

Almost there, you have to include b, your y-intercept

Answer 35

y=-1x+1

Answer 36

yup, but you don't have to include the 1, so y=-x+1

Answer 37

ok thank you very much

Answer 38

No problem, any other questions?

Answer 39

Nope think I understand it enough to learn the other problems =p

Answer 40

Ok, Good Luck!