How do I solve binomial expansions?
(x^2-4y^3)^5 with Pascal's Triangle

Question

anonymous · Answer

expand it completely, hint
(x^2-4y^3)(x^2-4y^3)(x^2-4y^3)(x^2-4y^3)(x^2-4y^3)
start with (x^2-4y^3)(x^2-4y^3)
add multiply the answer to that with the third (x^2-4y^3) then the fourth then the fifth.
Simplify

directrix · Answer

@sareenak   

Do you know what Pascal's Triangle is and how the entries in the triangle relate to the coefficients of the expansion of (x^2-4y^3)^5 ?

@ehuman did not incorporate Pascal's Triangle into the post above, as best I can tell.

directrix · Answer

@sareenak If you'd prefer to do this problem on your own, read the instructions at this link: http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-pascal-2009-1.pdf

anonymous · Answer

Thank you!

directrix · Answer

You are welcome.