6x - 2y=4 y + 2=3x.....I need help showing that this is a dependent equations.
Ok first we need to solve for x or y in one equation so lets start off by doing this making y+2=3 into y=3x-2
Now we know what y equals so we then plug in y into 6x-2y=4
Are you getting it so far?
so i plug y=3x-2 after the 2 in 6x-2y=4?
yes :) so it will be 2(3x-2)
Because y =3x-2 you can plug in that after the 2
Now solve for x
and tell me what you get
x=0
ok lemme check your awnser
Yes that is correct :D
So this proves that one equation is dependant on the other equations set of values
then i plug the 0 for x in 6x-2y=4 to solve for y?
correct
so how would it look like when I graph it?
0=3x-2 2=3x x=2/3
Lemme refresh my memory a bit sorry
Actually we are sposed to solve both equations for Y, silly me. Ok so we know y=3x-2 but also we need to solve for y in 6x-2y=4 So we change 6x-2y=4 to -2y=4-6x Then we divide both sides by -2 to get y=3x-2 So since they both are the same line you just graph 3x-2
Sorry about that I was in the wrong mindset
it's ok
So it should look something like this |dw:1381413264860:dw|
Because both equations produce the same line and are consistant so therefore they are dependant of eachother Its a phrase you can use if you are instructed to explain your awnser
thanks so much!
Not a problem :)
You can add me as a fan if you wish for my help whenever im online
Ill be glad to help you again
Thanks again for your help
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