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Choose the equation of the line that contains (4,4) and (-2,0). Y=-2/3x-4/3, y=4/3x+17/3, y=5
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the slope of the line that contains both points is \[ m=\frac{4-0}{4-(-2)}=\frac{4}{6}=\frac{2}{3} \]
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Write the equation in slope-intercept form of the line that has a slope of 5 and y-intercept of -3.
the equation of a line of slope m and y-intercept b is \[ y=mx+b \]
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i kinda get that just cant figure it out
the slope has to be m=5 and the y-intercetp b=-3, so the equation is \[ y=5x+(-3) \] \[ y=5x-3 \]
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