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Probability question: An experiment has three possible outcomes A, B and C with respective probabilities p, q and r, where p+q+r=1. The experiment is repeated until either outcome A or outcome B occurs. Show that A occurs before B with probability p/(p+q).
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your favorable cases are A occurs in first trial C occurs in first trial and then A occurs in 2nd. C occurs in 1st and 2nd trial, and then A in 3rd. and so on.. so required probability is : p + rp + r^2 p + r^3 p ... you should be able to simplify it from here on. note that 0<p,q,r<1 hope this helps
sounds like a trinomial distribution ....
sorry for that. mistake
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