Simplify the expression 2/x-6+4x
do you mean \[\frac{ 2 }{ x }-6+4x\] or \[\frac{ 2 }{ x-6 }+4x\] or \[\frac{ 2 }{ x-6+4x }\]
I mean the 2nd equation you listed
i supposed you would give them a common denominator so \[\frac{ 2 }{ x-6 }+4x \rightarrow \frac{ 2 }{ x-6 }+\frac{ 4x(x-6) }{ x-6 }\] then add and distribute so \[\frac{ 2+4x(x-6) }{ x-6 } \rightarrow \frac{ 2+4x ^{2}-24x }{ x-6 } \rightarrow \frac{ 4x ^{2}-24x+2 }{ x-6 }\]
Oh ok that makes more sense then the answer I had gotten. Would you mind helping me with another one? I am not positive that I got the right answer.
sure :)
ok thank you! it is x/x+5+5x/x-5 It is the same kind of one that you did above.
you mean \[\frac{ x }{ x+5 } + \frac{ 5x }{ x-5 }\]
yes
multiply each value by\[\frac{ (x+5)(x-5) }{ (x+5)(x-5)}\]
so you get \[\frac{ x(x-5) }{ (x+5)(x-5) }+ \frac{ 5x(x+5) }{ (x+5)(x-5) }\] then distribute and add like the previous problem
my mistake, correction: multiply each value by (x+5)/(x+5) or (x-5)/(x-5) as needed to give the values a common denominator so that you can add them together.
i got 6-5x?
@jigglypuff314
do you know how to distribute?
I think i am distributing wrong, could you show me please?
\[x(x-5) \rightarrow x ^{2}-5x\]
\[5x(x+5) \rightarrow 5x ^{2}+25x\]
ok so now I got 6x^2+20x/x^2-25?
yes
do I need to simplify it even more?
I am not sure what sort of math class you are in nor do I know what your teacher expects but I don't think you can simplify it even more.
Ok thank you very much for your help!
your welcome :)
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