Question

The perimeter of a trapezoid is 39a-7. Three sides have the following lengths: 9a, 5a +1, and 17a -6. What is
the length of the fourth side?

Answer 1

\(\bf \\textit{let's say our 4th side is }\quad n\\
perimeter = 39a-7\qquad sides\quad 9a,\quad 5a+1,\quad 17a-6,\quad n\\ \quad \\
\textit{recall that }\quad perimeter = \textit{sum of all sides}\\ \quad \\
39a-7= 9a+(5a+1)+(17a-6)+n\\ \quad \\\implies 39a-7= 9a+5a+1+17a-6+n\)

solve for "n", the 4th side will be in terms of "a"

Answer 2

hmmm

Answer 3

\(\bf \textit{let's say our 4th side is }\quad n\\
perimeter = 39a-7\qquad sides\quad 9a,\quad 5a+1,\quad 17a-6,\quad n\\ \quad \\
\textit{recall that }\quad perimeter = \textit{sum of all sides}\\ \quad \\
39a-7= 9a+(5a+1)+(17a-6)+n\\ \quad \\\implies 39a-7= 9a+5a+1+17a-6+n\)

Answer 4

solve for "n", the 4th side will be in terms of "a"