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YsinX+e^x=Y^2 Implicit differentiation?
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ahh now we have a question in this case you are thinking of \(y\) as a function of \(x\) although you don't know what it is (that is why it is "implicit" i.e. it is implied that \(y\) is a function of \(x\) start with the product rule \[y'\sin(x)-y\cos(x)+e^x=2yy'\] and solve for \(y'\)
i got this part and y'=(-ycosX-e^x)/9SinX-2y but i just wanna know the whole thing cause i got a really nasty answer at the end
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