Solve the linear system: x+2y=2 x-2y=6
x+2y = 2 ---- call this equation (1) x-2y = 6 ----call this equation (2) use (1) + (2) you get 2x = 8 so x = 8/4 = ? after you get the value of x, substitute x into either one of the two equations, you will have the value of y
2x=8 so x = 8/2 = ? is what @linkinage meant
4?
I guess the 8/2 = ?part is the "guiding the user to the answer" :P lol
You have to solve for each unknown by eliminating them one at a time. Add equation A and B A) x+2y=2 B) x-2y=6 2x = 8 so x =4 Try solving for y.
do we subtract now to solve for y?
there are several ways to do this. by subtracting two equations you can get the value of y as well. XD
Now that x has been eliminated, solving for y is easier. Substitute 'x' into either equation A or B will easily solve for 'y' So let's pick equation A and substitute the 'x' with 4 x+2y=2 4 + 2y = 2 Now can you solve for 'y'?
6y=2 y=3?
No 4 + 2y = 2 Subtract 4 from both sides
y=-2?
I'm guessing you did this 4 -4 + 2y = 2 -4 2y = -2 divide both sides by 2
y=-1
You've got it !!
thank you!!
u r welcome :-)
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