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How would you differentiate? f(x) = (3x^4 + 8)^2 what rule?
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Hmm looks like chain rule. We start with power rule on the outer function (leaving the inside the same).
2(3x^4+8)
Good, now chain rule tells us to make a copy of the inner function, take it's derivative and multiply.
\[\Large f'(x)\quad=\quad 2(3x^4+8)\color{royalblue}{(3x^4+8)'}\]
But then on the inside..? (3x^4+8) 12x^3
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Hmm? :o
So my answer is 2(3x^4+8)*12x^3? Then multiply 2 and 12x^3 and get 12x^3(3x^4+8)?
24x^3* yah :) you've got the right idea !
Sorry I mean 24 for the final answer
Then for my test I have to distribute it :(
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