Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (jacobbirddog):

whoever answers this correctly gets a fan!!!! Apples sell for $1.90 per pound, and bananas sell for $0.75 per pound. Troy bought some apples and some bananas. Together they weighed 3.8 pounds, and cost $5.84. Let a represent the number of pounds of apples Troy purchases. Which expression represents the number of pounds of bananas he purchases? A. 3.8a B. 3.8 – a C. a + 3.8 D. a – 3.8

OpenStudy (anonymous):

B, because you take the total pounds, which is 3.80 and subtract it by the weight of the apples to find the weight of the bananas.

OpenStudy (jacobbirddog):

ty! @tn.x680

OpenStudy (anonymous):

You're welcome!

OpenStudy (jacobbirddog):

tn i have another one!

OpenStudy (jacobbirddog):

Carrots sell for $2.10 per pound, and crackers sell for $2.90 per pound. Glen bought some carrots and some crackers. The total weight was 2.3 pounds and cost $6.03. Let p represent the number of pounds of carrots. Which equation represents the situation described? A. –0.8p + 6.03 = 6.67 B. 2.1p + 2.9 = 6.03 C. –0.8p + 6.67 = 6.03 D. 2.1p + 6.03 = 2.9

OpenStudy (anonymous):

B, because carrots are $2.10 per pound, and p represents pounds, so 2.1p would give you the price of the carrots. Crackers are 2.90 so you add that to the previous and set it equal to the total price, 6.03. 2.1p + 2.9 = 6.03

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
5 hours ago 3 Replies 0 Medals
Arriyanalol: help
5 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
8 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
8 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!