someone please help. Which conjunction or disjunction is equivalent to the given absolute value inequality? |x + 2| < 18 a. x + 2 > 18 or x + 2 < 18 b. x + 2 > 18 and x + 2 < 18 c. x + 2 < 18 or x + 2 > 18 d. x + 2 < 18 and x + 2 > 18
\(|x+2|<18\\\implies-18<x+2<18\\\implies-18-2<x<18-2\\\implies-20<x<16\) So, \(|x+2|<18\implies x+2 < 18 \) and \( x+2 > -18\) I don't see that option among yours.
the negitives didnt go tthru. u are correct :)
Ok.
thanks:)
You're welcome :)
You should close this one and give me a medal or something, otherwise people will just come and and look at this problem and see that it is solved. It's up to you ;)
lol how do u give medals?
When you click on "Best Response" that's a medal. You just gave me a one. :)
ohh hah sweet can u help my with another similar problem but walk me thru it pleaese?
But if you decide later that you don't like me, you can take it back and give it to someone else :( But you won't do that, right?
haha i will not :)
I'm here for you, at least for a little while
okay thanks so much :))))
k, shoot
okay l x l < 3
how would u do that if ur solving for the same thing as the first problem?
If I need to leave, feel free to send me a note \(|x|<3\) means this: \(-3 < x < 3\). It's THAT easy! Now, \(-3 < x < 3\) means: \(x < 3 \) and \(x > -3\). ALWAYS the same pattern.
So if you had something else other than "x", just replace EVERYTHING between the "| |" where I have "x" above and repeat. Say you had |x +2| < 3, this means: $$ |x+2| < 3 -3 < x+2 < 3 $$ Notice when I put the -3 there I REMOVED the "| |" part?
Let me rewrite that equation: $$ |x+2| < 3\\ \text{ means}\\ -3 < x+2 < 3 $$
thankss so muchh :))
Does it make sense? Really?
yesss
k
okay im having trouble with another one but the multiple choice dosnt look formilar.. its in a different format :(
|2x + 3| < 11
and the choices areee...
ok well that didnt work.. imma try to type it
a. xE (-7,4)
k
b. (-14,8)
Link above says "access denied, you need super human capabilities to access" or something like that
c. (11,infinity)
lol iknow thats why im just typing it :0
or d. (-8,11)
|2x + 3| < 11 Ok, imma let you do this What does it mean and REALLY try please!! And don't get mad at me an revoke my medal
x is less than 11.. ? right
2x + 3 < 11 That's the 1st step, what else?
do u have to do 3-3 and 11-3? .. or no
Not yet
o
2nd step: -11 < 2x + 3 See that? Same pattern.
Where did the -11 come from?
because u subtracted it from 11
Whenever you have something like |blah blah blah| < something This means - something < blah blah blah AND blah blah blah < something
ohh i get it now
So, "something" here is "11"
That's why the -11
so it became "-something"
yay!!!!
whats the next step
ok So we have $$ |2x + 3|<11\\ -11 < 2x+3 < 11 $$ Now we need to rearrange the blah blah part so that we only have "x" by itself there. We do that by 1st subtracting -3 from -11 and from 2x +3 and from 11 like this: \(-11 -3< 2x+3 -3< 11-3\) This gets rid of the 3 in the blah blah part of the equation
Now we have: -14 <2x<8
See that?
yesss.
But we don't have x by itself yet. how do we make it so x is there alone in the center. We have 2x and we want to make it "x" alone. What do we need to do?
What can we divide 2x by to get just "x"?
2
do u do that to -4 and 8 too?
yep. BUT, whatever we do to 2x we also must do to those endpoints, which we are calling "something" I see you already saw that coming!! Nice. Nice!!!
Do it!!
:) haha but how do u solve for y?
then i have -2<x<4
Finish the problem! Your are practically there. No, don't solve for anything, just divide
--^
-14 <2x<8 Dividing EVERYTHING by 2, we get -14/2 < 2x/2 < 8/2 Please, you can do this... what ya get?
oops i did -4/2 instead of -14
well?
-7<x<4
yaaaay!!!
So this means what?
something is less than something AND -something is less than something... Help me...
-7, 4 !! :D
yesss omg thank u so much :D
Yea, -7 < x AND x < 4, Right?
you get a medal!!
right, thanks so much. ur an awesome teacherrrrr!:)
It's slow to learn but better to do it yourself and understand
ur awesome, too
yeah.. the school that im attending is k12 and i pretty much have to teach myself everything and it sucksks :(
It was a pleasure helping you
if i ever need help in the future can i messga u ?
:)
yep, anytime
sweet :D
sweet
take care
you tooo!
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