Question

find an equation for the tangent line to the curve y=8/sqrt4+3x at the point (4,2).

Answer 1

Your answer will look like y = mx + b.

First step: find the slope, m, by:

Finding the derivative, y', of y=8/sqrt4+3x

THEN once you have y', plug in the x-coordinate from the point (4,2) and find what y' is equal to... that's your slope m.

Answer 2

I think I have to be doing something wrong....This is how I have it (0)(sqrt(4+3x)-(1/2(4+3x)^-1/2)(8)/(sqrt(4+3x))^2 and im not getting it right.