Question

12

Answer 1

How many cards are in each suit?

Answer 2

4

Answer 3

@Becki there are 13 suits and 4 cards in each

Answer 4

No. Other way around.

Answer 5

but there cant be 4 suits bc its a standard deck and a stnadard deck has 13 suits containing 4 types of cards eg: (A,2,3,4,5,6,7,8,9,10,Jack,K,Q) with (hearts, spades, etc)

Answer 6

No, the suits are Hearts, Spades, Diamonds and Clubs...

Answer 7

ohh ok

Answer 8

So, how many cards are in each suit?

Answer 9

13?

Answer 10

Yes, out of 52 cards, right? So what are your chances of drawing a card from, say, the hearts?

Answer 11

13/52

Answer 12

Right. So, without replacement, that is, without putting that card back in the deck, what are your chances of drawing another card the same suit as the first? Think about how many cards are left in the suit and how many are left in the deck.

Answer 13

12/52?

Answer 14

Close...it would be 12/51 because you didn't put that card back.

Answer 15

ohhh right

Answer 16

and now do i add the two number? (13/52) + (12/51)

Answer 17

So, since your question asked what are your chance of drawing 2 cards from the same suit, the first card really doesn't matter. What determines your probability is the second card. Get it?

Answer 18

If it had said, "What are your chances of drawing 2 hearts?" then the first card would matter, because you want it to be heart.

Answer 19

i see....and what would be the next step?

Answer 20

That's it as far as your original question. The probability of drawing 2 cards from the same suit is 12/51.

Answer 21

really? i thought i had to add the two numbers together to get the probability

Answer 22

No. Like I said, if your question had said 2 hearts or whatever, then you would MULTIPLY the probabilities, but since in your case, the first card doesn't matter, we don't do anything with it.

Answer 23

ohh i get it now...thank you so much for your help!!

Answer 24

No problem. :)

Answer 25

...just a side-note... if you really want to add stuff up, you can always think of it as the sum of the probabilities of drawing two hearts, two spades, two diamonds, and two clubs...

You'll end up with the same answer.