Question

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Answer 1

I don't understand your question. You want an angle in quadrant 3 but 78.99 is in quadrant 1, and secant (-5.2408) = 1.953490535...

Answer 2

If your calculator does not have sec, you can invert things and work with the cos.

Answer 3

It only has sin cos tan yes

Answer 4

i did cos^-1(5.2408) and got 79 but that cant be the angle because its not between 180 and 270

Answer 5

Yah, use the identity \(\dfrac {1}{\sin\theta}= \sec\theta\)

Answer 6

Oops. I meant cos there. LOL

Answer 7

\(\dfrac {1}{\cos\theta}= \sec\theta \implies \dfrac {1}{\cos\theta}=-5.2408\implies \)

\(\cos\theta=\dfrac {1}{-5.2408}\)

Answer 8

So what is \(\cos^{-1}\left(\dfrac {1}{-5.2408}\right)\)

Answer 9

101

Answer 10

but that's not between 180 and 270 either

Answer 11

Ah, but this is cosine. An x vlaue. What other angle is in the proper quad, but with the right x vlaue?

Answer 12

sin..

Answer 13

No, no... by x value.