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Find the surface area of the right triangular prism below
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@dopegyal_ So what do you think is the way to go about this?
well...SA= bh + 2ls + lb
Find the area of all the faces and add them up! You don't have to remember any particularly sophisticated formulas and it always works. (At least, unless there's some weird face you can't find the area of. Then... do something fancy. But otherwise.)
There's a right triangle for the bases. If you remember your Pythagorean Triples, you know the missing side of the triangular base is 10. SA = p*h + 2*B where p is the perimeter of the base and h is the height and B is the area of the base. SA = (8 + 6 + 10) * 15 + 2 * (1/2) * (8 * 6) SA = ?
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@dopegyal_
408?
That is what I got.
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